Thanks guys!
Use the standard reaction enthalpies given below to determine DH°rxn for the following reaction:
2 NO(g) + O2(g) → 2 NO2(g) DH°rxn = ?
Given:
N2(g) + O2(g) → 2 NO(g) DH°rxn = +183 kJ
1/2 N2(g) + O2(g) → NO2(g) DH°rxn = +33 kJ
Question 7 options:
-333 kJ
-150. kJ
+238 kJ
-117 kJ
+115 kJ