# Line slope calculator x+8y=26

**Straight line given by points A[2; 3] and B[10; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.125x+3.25

**Canonical form of the line equation:**x+8y-26 = 0

**Parametric form of the line equation:**

x = 8t+2

y = -t+3 ; t ∈ R

**Slope:**m = -0.125

**Slope angle of line: φ =**-7°7'30″ = -0.1244 rad

**X intercept:**x

_{0}= 26

**Y intercept:**y

_{0}= q = 3.25

**Distance line from the origin:**d

_{0}= 3.2249

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; -1)

**Normal vector: n =**(1; 8)

**Midpoint of the segment AB: M =**[6; 2.5]

**Perpendicular Bisector equation:**8x-y-45.5 = 0

**Vector OA = (2; 3) ; |OA| = 3.6056**

**Vector OB = (10; 2) ; |OB| = 10.198**

**Scalar product OA .OB = 26**

**Angle ∠ AOB = 45° = 0.7854 rad**