Fucks sake I'm on school break and I have to watch this...Why God, WHY?
Good work Alen, I knew you could do it lol.
Good work Alen, I knew you could do it lol.
Buy on AliExpress.com
Happy Birthday! (2 Viewers)
- Thread starter /usr/bin
- Start date
Buy on AliExpress.com
If no two share a birthday then the first person can choose a birthday
in 365 ways, the second person in 364 ways, the third in 363 ways, and
so on. If there are n people in the room, the probability that no two
share a birthday is
365 x 364 x 363 x ... x (365-n +1) P(365,n)
---------------------------------- = --------
365^n 365^n
So the probability that two at least share a birthday is:
If this must be >= 0.5 then we require -------- <= 0.5
..........................................................365^n
(Here, P(365,n) is the number of permutations of n things that can be
made from 365 different things)
There is no easy way to solve the equation for n, but with a
calculator which gives permutations and combinations, trial and error
will quickly establish that n must be around 23.
P(365,23)
--------- = 0.4927
365^23
and 1 - 0.4927 = 0.5073
and so 23 people are sufficient to make the probability of a shared
birthday greater than 50%. this means that 33 people are more than enough.
Give me my money
in 365 ways, the second person in 364 ways, the third in 363 ways, and
so on. If there are n people in the room, the probability that no two
share a birthday is
365 x 364 x 363 x ... x (365-n +1) P(365,n)
---------------------------------- = --------
365^n 365^n
So the probability that two at least share a birthday is:
P(365,n)
1 - --------
365^n
.........................................................P(365,n)1 - --------
365^n
If this must be >= 0.5 then we require -------- <= 0.5
..........................................................365^n
(Here, P(365,n) is the number of permutations of n things that can be
made from 365 different things)
There is no easy way to solve the equation for n, but with a
calculator which gives permutations and combinations, trial and error
will quickly establish that n must be around 23.
P(365,23)
--------- = 0.4927
365^23
and 1 - 0.4927 = 0.5073
and so 23 people are sufficient to make the probability of a shared
birthday greater than 50%. this means that 33 people are more than enough.
Give me my money
Get out of here.
Indeed.
I don't know...I guess she finds it hard to give you that money. Or she had to run to school to tell the answer because she couldn't answer it herself.
I don't know...I guess she finds it hard to give you that money.
Or she had to run to school to tell the answer because she couldn't answer it herself.
P.s: And Hoori paid me the money right away. I had 30k now i have 130k.
Oh, you're shooting high i see.
Expect a disappointment
Expect a disappointment
nije bas i bilo kao sto izgleda, ja nju znam od skoro i znam da je drugarice iz mog odeljenja mrze (a mene one nerviraju
)pa sam hteo da ih zajebavam malo i uspelo je .Odma ko da ih je pukla ljubomora i krenula da kreste...guske glupe. Ali Boze moj, dobra je skorz.
sorry for this...last time.
nije bas i bilo kao sto izgleda, ja nju znam od skoro i znam da je drugarice iz mog odeljenja mrze (a mene one nerviraju)pa sam hteo da ih zajebavam malo i uspelo je .Odma ko da ih je pukla ljubomora i krenula da kreste...guske glupe. Ali Boze moj, dobra je skorz.
nije bas i bilo kao sto izgleda, ja nju znam od skoro i znam da je drugarice iz mog odeljenja mrze (a mene one nerviraju
)pa sam hteo da ih zajebavam malo i uspelo je .Odma ko da ih je pukla ljubomora i krenula da kreste...guske glupe. Ali Boze moj, dobra je skorz.
Don't lie Dusan, you're in deep shit, you're in love.
